Good shit.
Very good.
Hehe, I just meant have wires so you could attach the battery. If those two wires arent connect to anything, take them off; the only wires going to IN and the ground pad next to IN is the battery.
And here we see it acting poorly. I’m sorry if you already know this, but I do have to verify something though. Because there might be a ripple in the outgoing current, you’re going to need to take measurements using both the AC and DC versions. Most meters have separate settings for AC voltage, DC voltage, AC current, and DC current. If the vpack is working perfectly, you should see 0 volts AC, and 5 volts DC, with 0 AC current and about 11-20 mA of DC current. If there is a repeating ripple in the outgoing power, then the AC numbers will be higher and the DC numbers lower. If the pack is working properly, it should be so low it doesn’t affect our stuff, but better to be thorough.
Do the same measurement, but use the AC voltage setting as well. Chances are that AC will show 0ish however, but best to cover all bases.
There is a chance the battery isn’t able to put out enough current to keep up with the demands. Take two of those 330 ohm resistors, and connect them in parallel. press one pair of legs against one battery terminal, and use the meter to measure the DC current between the other resistor legs and the other end of the battery. If the battery has plenty of juice, we should see 9 milliamps of DC current, so the 20mA setting is fine; do not use a lower setting! If you have to move the red probe over to a separate spot for measuring current, make sure to do so. Mine have a ‘mA’ spot for the red probe for this.
If the battery isn’t outputting about 9mA, then it may not be able to feed enough current to keep the vpack happy even with the lone resistor. Use a fresh battery. If the battery can output 9mA-ish, then see about a replacement from sparkfun.
EDIT: Whoa, holy crap. I just crunched the numbers, and to get the 15 mA out needed for that resistor from a single 1.5V battery, it has to pull 62.5 mA. That’s hugemoungous. We may want to use two AA or AAA (or even C’s or D’s if you have them) in series as a 3.0v source. Then it’d only have to produce 31mA to do 15mA at the resistor
REEDIT: Maybe this is a suitable replacement? http://www.sparkfun.com/commerce/product_info.php?products_id=8999
Cheaper, too.