Calc 2 isn’t that bad…
Just get your integration skills up there…
Series and Sequences are easy in comparison to all of the integration stuff you have to handle…
Taylor series were fun and very cool…
I don’t find it to be accurate at all. Most students have a lot of dififculty with limits and derivatives. I don’t see any reason why Calc II is a “weeder course” over other courses required to be an engineer. The idea that all calc I is is just plug and chug is an oversimplification. Yes, relative to integration, differentiation is simpler, however, that is not to say it too doesn’t require any thought. You need to do algebra to simplify some limits before you can plug and chug. Related rate problems are anything but plug and chug if you haven’t done a lot of those kinds of problems before. Then there’s problems requiring you to use the definition of a limit to solve, the concept of continuity, … It’s really not that cut and dry. Both require the ability to do algebra, trig, and geometry like its nothing. Those are your so called “weeder courses.”
And if you think differentiation is just about memorizing a bunch of formulas, find the derivative of this function (if it exists at all):
f(x) =
x^2 + x if x = 1/n, with n a natural number
0 if x = 0
at x = 0. Then at x = 1.
Well, to be fair, that won’t really come up in 99% of calc 1 classes (especially if that’s not a typo and the domain really isn’t an interval).
I agree with everyone that calc 2 shouldn’t be much harder than calc 1 though. I also wouldn’t put too much stock is doing complicated or tricky integrals, except for the fact that you need to for the tests of course. The reason is that a lot of them can be done much easier by using more advanced methods (from complex analysis, for example), and also, there are integral tables. Doing tricky integrals is not really the point of calculus imo. Taylor series, and just series in general, are really important and more interesting than complicated integrals. Then again, I never was that great at those hard integral problems and would probably fail a test with a lot of them on it, so I might be biased.
I mean if you can’t pull a passing grade in Calc 2, then you have no work ethic whatsoever…
Take notes and learn outside of class… do problems… etc…
There are lots of algebra tricks that you’ll have to learn to succeed… here’s one example…
Complete the Square
x^2+8x-2
[spoiler=]x^2+8x+16-16-2
(x+4)^2 -18
[/spoiler]
todays date is a fibonacci sequence!
i was working on some homework when i got stumped on how to find the integral for
x^3/(x^2)+1
can anyone help run me through the steps?
Do the polynomial long division first, then you should be able to make a u-substitution.
(x^3)/( (x^2)+1) = (x^3 +x -x) /(x^2 + 1) = x - x/(x^2 + 1)
What BBQ said is the routine way to do what I just did. Either way, you should be able to find the appropriate integrals now.
i started college in calc 3, so i can’t speak personally, but i recall calc 1 being pretty effective at weeding people out based on people bitching and dropping it. even calc for business got the job done even though i considered it jokes after seeing the textbook/homework.
Calc I wasn’t that bad, for me it was Calc II that crushed me into paste >_<
Reading through my physics I came across a problem that had the answer but when I tried to work it I never got the same result. Any way the equation is
((2)21m/s)^2/(2.5m/s^2)
The answer in the book says the answer is 350m
First week in physics has me stressing. Any tips for this course.
I’m rather sure that’s 705.6 m. However (2)(21 m/s)^2/(2.5 m/s^2) = 352.8 m, which would be 350 m if you’re paying attention to significant figures (and assume the “2” is exact…). Which I guess you ought to in a physics class?
i have no idea what that means. is that acceleration or speed? and why are they asking arithmetic on a physics test?
Yeah sorry put its actually (2)(21m/s)^2
So then I’m assuming that you get 352.8 m instead of the book’s 350 m, which I’d guess is because the book is maintaining 2 significant figures. (In which case I hope the book has mentioned “significant figures” somewhere.)
The basic idea of significant figures is that you can’t make your measurements more accurate just by doing math. As a simple example, if I measure the circumference of a circle with a tape measure and get 4.0 inches, I can’t claim that the diameter is 4.0/π = 1.273239544735162686 because there’s no way I could read a number that exact off of my tape measure.
The numbers in the problem have two significant figures, so the answer should have two significant figures too (since we’re only multiplying and dividing). That is if the “2” is exact and not a measurement. For example, if I measure a radius and want to multiply by 2 to get the diameter then the 2 is part of the definition of diameter, not something being measured, so I can treat it like it has an infinite number of significant figures.
And of course now that I typed that it occurs to me that Wikipedia, of course, has an article on this.
Yes, learn the definitions of words and apply them instead of thinking Physics is about memorizing a bunch of formulas. If you think memorizing formulas will help you do well in a Physics class then just tell your professor you want your F now instead of waiting until the end of the semester.
physics tips? always remember what exactly units stand (eg 1 Newton = 1 kg*m/sec^2, etc…)
,.oh and when in doubt, remember that almost all physics before E&M boils down to f=m*a.
- Do your homework early
- Don’t slack off
- Ask questions immediately while doing 1) and 2)
- When in doubt, see 2)
Appreciate the feedback.
thanks for all the help.
Business calc is 100% jokes, they barely learn derivatives before the semester is over…